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-8x^2+13x+6=0
a = -8; b = 13; c = +6;
Δ = b2-4ac
Δ = 132-4·(-8)·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*-8}=\frac{-32}{-16} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*-8}=\frac{6}{-16} =-3/8 $
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